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Since a phase shift of $180$ degrees is irrelevant, one can equivalently invert the $I$ component.
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This process of inversion and conjugation in the frequency domain corresponds to complex conjugation of the complex baseband signal in the time domain, which is equivalent to simply inverting the $Q$ component. So one side-band can be obtained from the other by inverting the frequency axis and by additional complex conjugation (in the frequency domain). This is necessary because due to different mixing conventions in several conversion stages, the upper and lower side-bands can be exchanged, and the two side-bands exhibit conjugate symmetry, because the transmitted signal is real-valued. The article Handling Spectral Inversion in Baseband Processing that you refer to in your question is not about simple inversion of the frequency axis, but it is about inversion of the frequency axis and conjugation in the frequency domain. Is there some other way to simply flip the spectrum around DC or should I try a two step process? Output: Ģ) Swap the I and Q channels swapTD = imag(timeDomain) + 1j * real(timeDomain) ģ) Invert the I channel negItd = -1 * real(timeDomain) + 1j * imag(timeDomain) Įach of these does flip the spectrum of the signal, but it also modifies the spectrum:ġ) Inverting Time Domain Q channel also negates/inverts the Frequency Domain Imaginary part.Ģ) Swapping the I and Q channels also swaps the Frequency Domain Real and Imaginary parts.ģ) Inverting the Time Domain I channel also negates/inverts the Frequency domain Real part. I looked on this website ( ) and the given proof states this can be done in 3 ways:ġ) Invert the Q channel negQtd = real(timeDomain) - 1j * imag(timeDomain) Is it possible to flip a signal's spectrum around DC? I have a simple spectrum that I made up (MATLAB code): spectrum =